[tex]2 \sqrt{3}=\sqrt{ 2^{2} +3}=\sqrt{4+3}=\sqrt{7}\\3 \sqrt{2} = \sqrt{ 3^{2}+2 } = \sqrt{9+2} = \sqrt{11} \\6 \sqrt{5} = \sqrt{ 6^{2} +5} = \sqrt{36+5} = \sqrt{41} \\-5 \sqrt{6}=- \sqrt{5^{2}+6} =- \sqrt{25+6} = -\sqrt{31} \\-4 \sqrt{7} =- \sqrt{ 4^{2} +7} =- \sqrt{16+7} =- \sqrt{23} \\ 7 \sqrt{3} = \sqrt{ 7^{2} +3} = \sqrt{14+3} = \sqrt{17} [/tex]
