👤
a fost răspuns

Sa se calculeze: a) (7 supra48+13supra24-3supra4)x6intreg si 2 supra5-16supra5(13supra5-5 intreg si 1 supra10)
b) (-3 supra7)x14supra11:33supra 484-(-2)la puterea3-(-3 supra2) la puterea2: 9 supra 4

Răspuns :

Spidie
a) (7/48 +13/24 -3/4) * 32/5 -16/5 *(13/5- 51/10)= (27/24- 36/48 ) *32/5 -16/5*
*(26/10-51/10)= 9/48 *32/5 -16/5* (-25/10)= 6/5 +8/5 =13/5

b) (-3/7)*14/11: 33/ 484-(-2)³-(-3 /2) ²: 9/ 4 = 6/11*33/484 + 8 +9/4 : 9/4=
= 9/242+8+1= 9/242+9=9/242+2178/242=2187/242

Alte intrebari