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Kidofthedarkness
a fost răspuns

Fie x∈(0,Π/2) /Calculati:
B=1/ (1+tg²x)+ 1/(1+ctg²)

Răspuns :

Lennox
+
1+tg²x=1+sin²x/cos²x=(cos²x+sin²x)/cos²x=1/cos²x
1+ctg²x=1+cos²x/sin²x=(sin²x+cos²x)/sin²x=1/sin²x
B=1/sin²x*1/cos²x=1/sin²x*cos²x

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