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Andreea12365
a fost răspuns

Calculati:
a) 3^3+3^20:3^18*3+3*3^8:3^6+3^10: (8*3^5+3^5)-4*3^3
b) [3+3*3^43+(7^5)^10:7^7^2]:[9^22+7^1^22+15^n+1:3^n]
VA ROGG MULT !!!!!

Răspuns :

Joitica
a) 3³+3²⁰:3¹⁸x3+3x3⁸:3⁶+3¹⁰: (8x3⁵+3⁵)-4x3³
=27+3²⁰⁻¹⁸x3¹+3⁸⁺¹:3⁶+3¹⁰ : (24+3)⁵-12³
=27+3²⁺¹+3⁹⁻⁶+3¹⁰ : 27⁵-12³
=27+3³+3³+3¹⁰ : (3³)⁵-12³
=27+27+27+3¹⁰:3¹⁵-12³
=81+3⁵-(12:4)³
=81+243- 3³
=81+243-9
=315

b) [3+3x3⁴³+(7⁵)¹⁰:7^7^2]:[9²²+7^1^22+15ⁿ+1:3ⁿ]

pe b nu il stiu.. sper ca te-am ajutat macar cu a) ^^

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