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a fost răspuns

Descompuneti in factori:
a) (3x+1)²-(x+3)²
b) (3x+5)²-(x+1)²
c) (x+√2)²-8

Răspuns :

Spidie
a) (3x+1)²-(x+3)²= (3x+1+x+3)(3x+1-x-3)=(4x+4)(2x-2)=4(x+1)*2(x-1)=
=8*(x+1)(x-1)=8*(x²-1)

b) (3x+5)²-(x+1)²=(3x+5+x+1)(3x+5-x-1)=(4x+6)(2x-4))=2(2x+3)*2(x-2)=
=4(2x+3)(x-2)

c) (x+√2)²-8 = (x+√2+4)(x+√2-4)

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