Răspuns :
[tex]a+b+c=123 \\
b=3a+2 \\
c= \frac{a+b}{2}= \frac{a+3a+2}{2} = \frac{4a+2}{2}= \frac{2(2a+1)}{2}=2a+1 \\
a+3a+2+2a+1=123 \\
6a+3=123\\~
6a=120 =>a=20~deci~b=62~si~c=41[/tex]
a+b+C=123
b=3a+2
c=(a+b):2
[a+3a+2+a+3a+2]:2=123
8a+8a+4=123supra2de aici sper sa rezolvi ecuatia, multa bafata!!
b=3a+2
c=(a+b):2
[a+3a+2+a+3a+2]:2=123
8a+8a+4=123supra2de aici sper sa rezolvi ecuatia, multa bafata!!