| 2x + 1 | = 0 daca : 2x + 1 ≥ 0 2x ≥ -1 x≥ -1/2 | 2x+1 | = 2x+ 1
2x +1 = 0 2x = -1 x = -1/2
ptr. 2x + 1 < 0 2x < - 1 x < -1/2 |2x+1| = 1-2x 1 - 2x = 0 x =1/2 > -1/2 x∈Ф
1 - 3x = 5
ptr. 1-3x ≥ 0 3x ≤ 1 x ≤ 1/3 |1-3x| = 1-3x = 5 3x = - 4 x = -4/3
ptr. 1-3x <0 x > 1/3 |1-3x| = 3x - 1 =5 3x = 6 x = 2
|x-1| = 3
ptr. x-1≥0 x ≥ 1 |x-1| = x -1 x-1 = -3 x = -2 <1 x∈Ф
