Răspuns :
2x+4 - x^2 - 5x= 2x-14
4 - x^2 - 5x + 14 = 0
-x^2 - 5x + 18 = 0
Δ = b^2 - 4ac
Δ = 25 - 4(-1)(18) = 25 + 72 = 97
x1,2 = (-b+- √Δ)/2a => x1= (5+[tex] \sqrt{97} [/tex])/ -2 si x2 = (5+[tex] \sqrt{97} [/tex])/ -2
4 - x^2 - 5x + 14 = 0
-x^2 - 5x + 18 = 0
Δ = b^2 - 4ac
Δ = 25 - 4(-1)(18) = 25 + 72 = 97
x1,2 = (-b+- √Δ)/2a => x1= (5+[tex] \sqrt{97} [/tex])/ -2 si x2 = (5+[tex] \sqrt{97} [/tex])/ -2