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a fost răspuns

1)2^5+2^6+2^8=11*2^2
2)2^[tex] \frac{2}{3} [/tex]+25^[tex] \frac{1}{3} [/tex]+8^[tex] \frac{1}{3} [/tex]

Răspuns :

1)
2^5+2^6+2^8=2^3*2^2+2^4*2^2+2^6*2^2=(2^3+2^4+2^6)*2^2=(8+16+64)*2^2=84*2^2 ...nu stiu dece ar fi 11*2^2.

2)
8^(1/3)=2, deci 2^(2/3)+25^(1/3)+8^(1/3)=2^(2/3)+5^(2/3)+2 ...in rest nu prea mai ai ce calcula.

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