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Bia444
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Determinati media geometrica a numerelor x= (√3 + √2) (√6 -√5) si y=(√3 - √2) (√6 - √5) .

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Răspuns :

Vilmaristul
Mg=√x*y
Mg=√(√3+√2)(√3-√2)(√6-√5)(√6+√5)
Mg=[(√3²-√2²)(√6²-√5²)
Mg=(3-2)(6-5)
Mg=1
[tex]\it m_g = \sqrt{x\cdot y} [/tex]

[tex]\it x\cdoty = (\sqrt3 + \sqrt2)(\sqrt6+\sqrt5)(\sqrt3 - \sqrt2)(\sqrt6-\sqrt5)=[/tex]

[tex]\it= (\sqrt3 + \sqrt2)(\sqrt3 - \sqrt2) (\sqrt6+\sqrt5)(\sqrt6-\sqrt5)= (3-2)(6-5) = 1[/tex]


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