Răspuns :
[tex] \frac{5}{x-2} - echiunitara.\x-2-divizor \ a \ lui \ 5. \ \ \ D5={1,5} [/tex]
[tex]dar\ fiind \ fractie \ echiunitara \ x-2=5=\ \textgreater \ x=5+2=\ \textgreater \ x=7, \ \frac{5}{7-2} [/tex]
5/5=1
[tex]dar\ fiind \ fractie \ echiunitara \ x-2=5=\ \textgreater \ x=5+2=\ \textgreater \ x=7, \ \frac{5}{7-2} [/tex]
5/5=1