Răspuns :
1)x/4;
2)Mai avea de mers x-x/4=3x/4.Deci a doua zi merge 3x/4/3=3x/12=x/4;
3)A treia zi i-a ramas x-x/4-x/4=2x/4=x/2.Deci a treia zi a mers x/2/2=x/4.;
4)50km;
x/4+x/4+x/4+50km=x;
x-3x/4=50km;
x/4=50km;
x=4•50=200km
n = drumul
/...../...../...../...../ = n
prima zi a mers 1/4 din n ( /...../ )
raman :
/...../...../...../
a doua zi 1/3 din rest ( /...../ )
raman :
/...../...../
a treia zi 1/2 din rest ( /...../ )
raman :
/...../ = 50 km.
n=50x4=200 km tot drumul
prima zi : 200:4=50 km
200-50=150 km. rest
a doua zi : 150:3=50 km
150-50=100 km rest
a treia zi : 100:2=50 km.
a patra zi = 50 km.
V: 50+50+50+50=200 km. intregul drum
/...../...../...../...../ = n
prima zi a mers 1/4 din n ( /...../ )
raman :
/...../...../...../
a doua zi 1/3 din rest ( /...../ )
raman :
/...../...../
a treia zi 1/2 din rest ( /...../ )
raman :
/...../ = 50 km.
n=50x4=200 km tot drumul
prima zi : 200:4=50 km
200-50=150 km. rest
a doua zi : 150:3=50 km
150-50=100 km rest
a treia zi : 100:2=50 km.
a patra zi = 50 km.
V: 50+50+50+50=200 km. intregul drum