Răspuns :
[tex]2 \sqrt{12} + \sqrt{27}-3 \sqrt{48}= \\ \\ 2 \sqrt{ 2^{2}*3} + \sqrt{3^{3} } -3 \sqrt{2^{4}*3} = \\ \\ 4 \sqrt{3} +3 \sqrt{3}-12 \sqrt{3} = \\ \\ -12 \sqrt{3} +7 \sqrt{3} = \\ \\2 \sqrt{12} + \sqrt{27}-3 \sqrt{48}= -5 \sqrt{3} [/tex]