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(X+1)^2supra3-(x-2)(x+2)supra4=(x-2)^2-6supra 12-5x+2supra6

Răspuns :

(X+1)²/3-(X-2)(X+2)/4=(X-2)²-6/12-5X+2/6⇒
x²+2x+1/3-(x²-4)/4=(x²-4x+4)-6/12-5x/6
4x²+8x+4-(3x²-12)/12=x²-4x+2-10x+4/12⇒
4x²-3x²+8x+16/12=x²-14x+6/12⇒
12(x²+8x+16)=12(x²-14x+6)⇒
12x²+96x+192=12x²-168x+72⇒

12x²-12x²+96x+168x+192-72=0⇒

264x+120=0⇒264x=-120⇒x=-120/264⇒x=60/132
x=30/66=15/233
succes