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a fost răspuns

Aflati x din egalitatea: 2×5^2-5×[3^2+5-3×(2x-2004^0)]=5^2

Răspuns :

Gabcen71
2*25-5*[9+5-3*(2x-1)]=25
50-5*[9+5-3*(2x-1)]=25
5*[9+5-3*(2x-1)]=25
9+5-3*(2x-1)=5
14-3*(2x-1)=5
3*(2x-1)=9
2x-1=3
2x=4
x=2
2*25-5*[9+5-3*(2x-1)]=25
50-5*[9+5-3*(2x-1)]=25
5*[9+5-3*(2x-1)]=25
9+5-3*(2x-1)=5
14-3*(2x-1)=5

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