a+b=a-b+316
(a+b) /(a-b)=3 r 50
a+b=(a-b)x3+50
din prima relatie
2b+a-a=316
2b=316
b=316/2
b=158
inlocuim in a doua relatie
a+158=(a-158)x3+50
a+158=3a- 474+50
3a-a= 158+474-50
2a=632-50
2a=582
a=582/2
a=291
verificare
291+158=291-158+316
449=133+316
449=449
