Răspuns :
Din egalitatea a/0,6 = b/0,9 rezulta ca b/a = 0,9/0,6= 9/6=3/2 si a/b = 2/3
deci (b/a)^0 + (b/a)^-1 + (b/a)^-2 = 1 + a/b + (a/b)^2 = 1+ 2/3 + 4/9= (9+6+4)/9= 19/9
deci (b/a)^0 + (b/a)^-1 + (b/a)^-2 = 1 + a/b + (a/b)^2 = 1+ 2/3 + 4/9= (9+6+4)/9= 19/9
a/b=0,6/0,9=6/9=2/3
b/a=3/2
a/b^0=(3/2)^0=1
b/a)^(-1)=(3/2)^-1=2/3
(b/a)^(-2)=(3/2)^-2=(2/3)^2=4/9
1+2/3+4/9=(9+6+4)/9=19/9
Ai inteles ?
b/a=3/2
a/b^0=(3/2)^0=1
b/a)^(-1)=(3/2)^-1=2/3
(b/a)^(-2)=(3/2)^-2=(2/3)^2=4/9
1+2/3+4/9=(9+6+4)/9=19/9
Ai inteles ?