[tex]Pentru\ a\ afla\ in\ cate\ zero-uri\ se\termina\ un\ produs\ ca\ acesta\\
vom\ folosi\ formula:\\
\boxed{[\frac{n}{5}]+[\frac{n}{25}]+[\frac{n}{125}]+...+ [\frac{n}{5^x}]},(unde\ [a]\ reprezinta\ partea\\
intreaga)\\
Inlocuim:\\
{[\frac{25}{5}]+[\frac{25}{25}]+[\frac{25}{125}]= (nu\ are\ rost\ sa\ mergem\ mai\ departe)}\\
{[5]+[1]+[0]=}\\
5+1+0=\boxed{6}\\
Asadar\ numarul\ se\ termina\ in\ 6\ zerouri.[/tex]
