Răspuns :
17. a + b = 26 daca, a >b a = c·b + r1 b = 0·a + r2 r2 = b
c + r1 = r2 = a - 8 ⇒ b = a - 8
a + a - 8 = 26 2a = 34 a = 17 b = 9
18. abcd = 100ab + cd = 100ab + 2ab = 102·ab = 17·6·ab ÷ 17 = 6·ab r = 0
19. m + n = 3(10 + 14 +.18+.....+210):(10 + 14 +.....+ 210) = 3
m - n = 11 - 100 : {28 + 3·24} = 11 - 1 = 10
b) a - b - c = 4 a - b - c - c = 2 4 - c = 2 c = 2 a - b = 6 ( a = 9 b = 3)
(a = 8 b = 2) (a = 7 b = 1) (a = 6 b = 0)
abc ∈{ 932, 822,712,602}
2a - b - c = 10 a + a - b - c = 10
a - b + c = 9 a - b + c = 9
------------------- ----------------------
3a - 2b = 19 a - 2c = 1 a - b = 9 -c c = 4 a = 9 b = 4 abc = 944
c) ab +
bc
ca
--------
abc a + b = 10 a + b + c + 1 = 10a + b
10 + c + 1 = 10a + b
1(c+1) barat = ab barat ⇒ a = 1 b = 9 c = 8 abc = 198
20. a1 = n·c1 + r1
a2 = n·c2 + r2
----------------------------
a10 = n·c10 + r10
r ∈ {0,1,2,....9} ⇒ a10 = n·c10 + 9 9 < n ⇒ n ≥ 10
b) S minim = 10·1 + (10·1 + 1) + (10·1 + 2) +........+ (10·1 + 9)
S = 10·10 + (1+ 2+ 3+......+9) = 100 + 45 = 145
c + r1 = r2 = a - 8 ⇒ b = a - 8
a + a - 8 = 26 2a = 34 a = 17 b = 9
18. abcd = 100ab + cd = 100ab + 2ab = 102·ab = 17·6·ab ÷ 17 = 6·ab r = 0
19. m + n = 3(10 + 14 +.18+.....+210):(10 + 14 +.....+ 210) = 3
m - n = 11 - 100 : {28 + 3·24} = 11 - 1 = 10
b) a - b - c = 4 a - b - c - c = 2 4 - c = 2 c = 2 a - b = 6 ( a = 9 b = 3)
(a = 8 b = 2) (a = 7 b = 1) (a = 6 b = 0)
abc ∈{ 932, 822,712,602}
2a - b - c = 10 a + a - b - c = 10
a - b + c = 9 a - b + c = 9
------------------- ----------------------
3a - 2b = 19 a - 2c = 1 a - b = 9 -c c = 4 a = 9 b = 4 abc = 944
c) ab +
bc
ca
--------
abc a + b = 10 a + b + c + 1 = 10a + b
10 + c + 1 = 10a + b
1(c+1) barat = ab barat ⇒ a = 1 b = 9 c = 8 abc = 198
20. a1 = n·c1 + r1
a2 = n·c2 + r2
----------------------------
a10 = n·c10 + r10
r ∈ {0,1,2,....9} ⇒ a10 = n·c10 + 9 9 < n ⇒ n ≥ 10
b) S minim = 10·1 + (10·1 + 1) + (10·1 + 2) +........+ (10·1 + 9)
S = 10·10 + (1+ 2+ 3+......+9) = 100 + 45 = 145