a) (1/8)^3
b) (3/4)^3 x (3/4)^5
c) (29/4)^15 : (29/4)^12
d) [(3/31)^4]^5
e) [2,(5)]^4 x [2,(5)]^5
f) (49/9)^21 :{[5,(4)]^4}^5
g) (75/19)^3 x (38/25)^3
h) (0,12)^7 x ( 8 intregi 1/3) ^7
b (3/4)³⁺⁵ c (29/4)¹⁵⁻¹² e [(23/9)²¹⁻⁴]⁵=(23/9)¹⁷*⁵ f (49/9)²¹:[(49/9)⁴]⁵=(49/9)²¹⁻²⁰ g (75/19x38/25)³=6³9dp.simplificari) h (12/100x25/3)⁷=1⁷(dp.simplificari)
