a. CH4 + O2 ---> CH2O + H2O
b. n=V/Vm=89.6/22.4=4 moli CH4
1mol CH4................1mol formol (CH2O)
4mol.......................4mol
n=m/M==>m=n*M=4*30=120g CH2O (md) MCH2O=30g/mol
Cp=md/ms*100==>ms=md*100/Cp=12000/40=300g CH2O (mt)
n(eta)=mp/mt*100==>mp=n*mt/100=80*300/100=240g CH2O (formol)