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LennaN
a fost răspuns

Daca a+b=32 si b+c=37, calculati 3a+7b+4c.
*Coronita*

Răspuns :

Dorlorenevelyn1
a+b+b+c=32+37
a+2b+c=69 I x 3
3a+6b+3c=69x 3
3a+6b+3c=207
         b+c= 37
____________+
3a+6b+3c+b+c=207+37
3a+7b+4c=244
R: 244



Sanduurzica
a+b=32  si b+c=37
3a+7b+4c=3a+3b+4b+4c=        ( il descompune pe 7b in 3b+4b)
3x32+4x37=
96+148=244

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