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Miha1234567890
a fost răspuns

[tex] \sqrt{3}+ \sqrt{12} -3 \sqrt{3} =0
[/tex]

Răspuns :

Alitta
√3 +√12 - 3√ = √12 = √(4*3) - 2√3 = 2√3 - 2√3 = 0


Icecon2005
[tex] \sqrt{3} + \sqrt{12}-3 \sqrt{3} =0 \\ \\ \\ \\ \sqrt{3} + 2\sqrt{3}-3 \sqrt{3} =0 \\ \\3 \sqrt{3}-3 \sqrt{3}=0 \\ \\ 0=0 [/tex]
12=4×3=2²×3 iar√(2²×3)=2√3


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