Răspuns :
[tex]a)x^2+5x+6=x^2+2x+3x+6=x(x+2)+3(x+2)=\\
=\boxed{(x+2)(x+3)}\\
\\
b)x^2-7x+12=x^2-4x-3x+12=x(x-4)-3(x-4)=\\
=\boxed{(x-4)(x-3)}[/tex]
a. x²+5x+6=x²+2x+3x+6=x(x+2)+3(x+2)=(x+2)(x+3)
b. x²-7x+12=x²-4x-3x+12=x(x-4)-3(x-4)=(x-4)(x-3)
b. x²-7x+12=x²-4x-3x+12=x(x-4)-3(x-4)=(x-4)(x-3)