m(∡A) = 90°
m(∡B) = 45°
AC = 5 cm
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m(∡C) = ?
AB = ?
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Sin(B) = [tex] \frac{AC}{BC} [/tex]
[tex] \frac{ \sqrt{2} }{2} = \frac{5}{BC} [/tex]
BC = 5√2
Cos(B) = [tex] \frac{AB}{BC} [/tex]
[tex] \frac{ \sqrt{2} }{2} = \frac{AB}{5 \sqrt{2} } [/tex]
AB = 5 cm
