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Andreiinculet
a fost răspuns

1-i supra√2 ,totul la putera 24

Răspuns :

[tex][ \frac{1-i}{ \sqrt{2} }]^ ^{24} =[ [ \frac{1-i}{ \sqrt{2} }] ^{2}] ^{12}= [ \frac{-2i}{2} ] ^{12} = \frac{-2i}{4096} = \frac{-i}{2048} [/tex]
C04f
[tex] [ \frac{1-i}{ \sqrt{2} }] ^{24} =( [ \frac{1-i}{ \sqrt{2} }]^2) ^{12}= ( \frac{1-2i+i^2}{2}) ^{12}= [\frac{1-2i-1}{2}] ^{12}=[(-i)^4]^3=1 [/tex]

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