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Roby11
a fost răspuns

Calculati:
(1+2x2 la puteria 2 x2 la puteria a 4):(2 la puteria 7 +1)
[(3 la puteria 3) totul la puteria 12 :3 la puteria2 si 5-56]:5
8 la puteria 16 :(2x2 la puteria 4 x2 la puteria 10) totul la puteria3 -2 la puteria1 -2 la puteria0
10 la puteria2 x[4+5x3 la puteria2 -2 la puteria5 +4 la puteria3x(49-3 la puteria2):2 la puteria3]
[7x(14-2x7):2]totul la puteria2
(10 la puteria2 -8 la puteria2):6:2+1 la puteria2003

Va rog mult!

Răspuns :

Anamariaangel
[tex](1+2* 2^{2} * 2^{4} ):(2 ^{7} +1)=(1+2 ^{1+2+4}) :(2 ^{7}+1)=(1+2 ^{7} ) :(1+2 ^{7} )[/tex]=[tex]1[/tex]
[tex] 8^{16} :(2*2 ^{4}*2 ^{10}) ^{3} -2-2 ^{0}= (2^{3})^{16}:( 2^{2+4+10} ) ^{3} -2-1=[/tex][tex] 2^{3*16} :( 2^{16}) ^{3} -3= 2^{48} :2^{48}-3=1-3=-2[/tex]
[tex]10 ^{2}*[4+5*3 ^{2}-2 ^{5} +4 ^{3} (49- 3^{2} ):2 ^{3} =[/tex][tex]= 10^{2} *(4+45-32 +64 *40:8)=10^{2}(17+320)=100*337=33700[/tex]
[tex][7*(14-2*7):2] ^{2} =[7*(14-14):2] ^{2} =(7*0:2) ^{2} =0[/tex]
[tex](10 ^{2}-8 ^{2} ) :6:2+1 ^{2003} =(100-64):3+1=36:3+1=13+1=14[/tex]


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