1. Folosim teorema lui pitagora:
NP²=MN²+MP²
NP²=324+576
NP²=900⇒NP=30 cm
5.Cu teorema lui pitagora aflam cat ii BD:
BD²=AB²+AD²
BD²=225+400
BD²=625⇒BD=25 cm
Fie AM perpendicular pe BD.
Cu teorema inaltimii aflam cat ii AM:
AM=AB*AD/BD
AM=15*20/25
AM=3*4= 12 cm
6.Aflam cat are si cealalta cateta:
AC²=BC²-AB²
AC²=400-144
AC²=256⇒AC=16 cm
P=AB+AC+BC
P=12+16+20
P=48 cm
