1) 62/495=0,1252525........25 = 0,1(25)
cel mai simplu, consideram 30 zecimale grupate in 15 perechi:
12 52 52 52.... 52
in concluzie a 30-a zecimala e 2
337/330=1,0212121.........21=1,0(21)
analog exemplului de mai sus:
02 12 12 12 ..........12 (15 perechi) deci a 30-a zecimala este 2
2) N=2^(n+2) +3x2^n=2^2 x 2^n + 3 x 2^n=2^n (4+3)=7 x 2^n ⇒ 7 | N
3) daca am inteles bine avem:
(3/4 x 17/6 - 5/2 : 4/3) x 8 =(17/8 - 5/2 x 3/4) x 8 = (17/8 - 15/8) x 8= 2/8 x 8=2
