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27^30 - 4 × 9^44 + 4^104 ÷ 2^207 - 5 × (3^44)^2-Calculati!!!!!
Va rog frumos!!!!!!
Rog Seriozitate!!!!
Ps-Rezultatul final trebuie sa fie-2!!!

Răspuns :

Bunicaluiandrei
3⁹⁰ - 4ₓ3⁸⁸ +2²⁰⁸ : 2²⁰⁷ - 5ₓ 3⁸⁸  = 3⁹⁰ - 4ₓ 3⁸⁸ + 2 - 5ₓ 3⁸⁸ =
= 3⁸⁸ (9 - 4 - 5) + 2 = 2
27^30-4*9^44+4^104:2^207-5*(3^44)^2=
=(3^3)^30-4*(3^2)^44+(2^2)^104:2^207-5*3^88=
=3^90-4*3^88+2^208:2^207-5*3^88=
=3^90-4*3^88+2-5*3^88=
=3^90-4*3^88-5*3^88+2=
=3^88*(3^2-4-5)+2=
=3^88*(9-4-5)+2=
=3^88*0+2=2

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