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Vladi4727
a fost răspuns

Stiind ca x=5 si y+z = 14, calculati : a) x+2y+2z; b)5x+3y+3z

Răspuns :

Cristinatibulca
a. x+2(y+z)=5+2x14=5+28=33
.b. 5x+3(y+z)=5x5+3x14=25+42=67
Danamocanu71
a. x+2y+2z=5+2•14=33
b. 5x+3y+3z=5•5+3•14=25+42=67

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