Răspuns :
n=V/Vm=0.56/22.4=0.025 kmoli= 25 moli SO2
1mol SO2...................6.023*10^23 molecule
25 moli.......................x=150.575*10^23 molecule
1mol SO2...................6.023*10^23 molecule
25 moli.......................x=150.575*10^23 molecule
1 mol SO2 = 6,022 * 10^23 molecule
1 mol ocupa in conditii normale 22.4 l
22,4 l SO2............ 6,022 * 10^23 molecule
560 l SO2.....................x molecule
x = 150,55 / 10^23 molecule
1 mol ocupa in conditii normale 22.4 l
22,4 l SO2............ 6,022 * 10^23 molecule
560 l SO2.....................x molecule
x = 150,55 / 10^23 molecule