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The13viper
a fost răspuns

[tex] \sqrt{} x^{2} +x+2 = x^{2} +x [/tex]

Răspuns :

Raluca98t
[tex]\sqrt x^2 +x+2 = x^2 +x \\ x + x + 2 = x^2 + x \\ 2x + 2 = x^2 +x\\ x ^2-x-2=0 [/tex]
Δ = 1+8 = 9
x₁ = [tex] \frac{1+3}{2} = 2[/tex]
x₂ =  [tex] \frac{1-3}{2} = -1[/tex]