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Bucurmaria03
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Descompuneti in factori x³-y³-xy²+x²y=

Răspuns :

Iakabcristina2
x³-y³-xy²+x²y=
x³-xy²-y³+x²y=
x(x²-y²)-y(y²-x²)=
x(x-y)(x+y)-y(y-x)(y+x)=
(x+y)[x(x-y)-y(y-x)]=
(x+y)[x(x-y)+y(x-y)]=
(x+y)²(x-y)

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