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a fost răspuns

determinati numerele naturale de 3 cifre scrise in baza zece care impartite la 38 dau restul 7?

Răspuns :

Renatemambouko
100<38a+7<999
93<38a<992
a={3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26}

nr sunt: 121,159,197,235,273,311,348,387,425,463,501,539,577,615,653,691,729,
767,805,843,881,919,957,995