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Marialarisa2
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Rezolva fata calcul scris operatiile:(89×89:89+1):90+1= ((989-989)×(1989×989×89×9)= [(1989+1989):2+11]:2000
Explicatim va rog la final :*

Răspuns :

GabyNico
(89×89:89+1):90+1= 2

(989-989)×(1989×989×89×9)= 0

[(1989+1989):2+11]:2000= 1

 
(89×89:89+1):90+1=(7921:89+1):90+1=(89+1):90+1=90:90+1=1+1=2


(989-989)×(1989×989×89×9)= 0×(1.967.121×89×9)=0×(175.073.769×9)=
0×1.575.663.921=0


[(1.989+1.989):2+11]:2.000= (3.978:2+11):2.000=(1.989+11):2.000=2.000:2.000=1

Raoull
(89×89:89+1):90+1=(89x1+1):90+1=90:90+1=1+1=2


(989-989)×(1989×989×89×9)=0x(1989×989×89×9)=0

**0 inmultit cu orice nr. este 0, de aceea nu am mai calculat in paranteza

[(1989+1989):2+11]:2000=(3978:2+11):2000=(1989+11):2000=2000:2000=1

La fiecare exercitiu se calculeaza conform regulii semnelor: mai intai se face inmultirea/impartirea iar apoi adunarea/scaderea (in functie de cum sunt in exercitiu)

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