Răspuns :
Inteleg ca avem proportia : [tex]\frac{x+2}{3}=\frac{3}{2}[/tex]
2*(x+2) = 3*3
2x+4 = 9
2x = 5
x = 5/2=2,5
2*(x+2) = 3*3
2x+4 = 9
2x = 5
x = 5/2=2,5
[tex] (x+\frac{2}{3}= \frac{3}{2})(x+ \frac{2}{3}= \frac{3}{2})
[/tex]
([tex](\frac{x+4}{6}=\frac{9}{6})(\frac{x+4}{6}=\frac{9}{6}) (6x+24=54)(6x+24=54) (6x+24-54)(6x+24-54) (6x-30)(6x-30)=(6x-30)^{2} 36x^{2}-360x+900=0|:36 x^{2}-10+25=0 delta=b^{2}-4ac delta=100-100=0 [/tex]
[tex]x_{1}=x_{2}[/tex] , deci:
[tex] x_{1}=\frac{-b+ \sqrt{delta}}{2a}=\frac{10+0}{2}=5[/tex]
[tex]x_{2}=\frac{-b-\sqrt{delta}}{2a}=\frac{10-0}{2}=5[/tex]
R: x=5
([tex](\frac{x+4}{6}=\frac{9}{6})(\frac{x+4}{6}=\frac{9}{6}) (6x+24=54)(6x+24=54) (6x+24-54)(6x+24-54) (6x-30)(6x-30)=(6x-30)^{2} 36x^{2}-360x+900=0|:36 x^{2}-10+25=0 delta=b^{2}-4ac delta=100-100=0 [/tex]
[tex]x_{1}=x_{2}[/tex] , deci:
[tex] x_{1}=\frac{-b+ \sqrt{delta}}{2a}=\frac{10+0}{2}=5[/tex]
[tex]x_{2}=\frac{-b-\sqrt{delta}}{2a}=\frac{10-0}{2}=5[/tex]
R: x=5