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a fost răspuns

afla cel mai mic numar natural care impartit pe rand la 6 15 si 24 da rasturile 4 13 si respectiv 22

Răspuns :

n=6c1+4 |+2
n=15c2+13|+2
n=24c3+22|+2
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     n=?
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n+3=6c1+6
n+3=15c2+15
n+3=24c3+24
n-3=[6,15,24]=24
6=2*3
15=3*5
24=2^3*3
[6,15,24]=2^3*3*5=120
n-3=[6,15,24]=120
n-3=120
n=120+3
n=123

Verificare:
123:6= 20 rest 3
123:15= 8 rest 3
123:24= 5 rest 3