Răspuns :
80% din 50 g = 1,6 g glucoza
1 mol... 180g glucoza ... 2817 Kj
............ 1,6 g glucoza.....x Kj
x=1,6 * 2817 / 180 = 25, 04 Kj
1 mol... 180g glucoza ... 2817 Kj
............ 1,6 g glucoza.....x Kj
x=1,6 * 2817 / 180 = 25, 04 Kj
0.8*50=40g C6H12O6
n=m/M=40/180=0.222 moli C6H12O6
1mol..............................2817 kj/mol
0.222mol...................x=625.99=626 kj/mol
MC6H12O6=180g/mol
n=m/M=40/180=0.222 moli C6H12O6
1mol..............................2817 kj/mol
0.222mol...................x=625.99=626 kj/mol
MC6H12O6=180g/mol