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Mugurmarinramni
a fost răspuns

Cum se calculeaza acest exercitiu [2+ 2^2x2^22 +2^200:2^120 +(3^3)^10] : [1+ 2^24+ 2^80+ 2^2013+ 3^30] -2+ (5^7)^3

Răspuns :

Dyana98
= (2+ 4 X 4194304 + 1.606938e + 60:1.329228e+36 +2.0589113e+14) : (1+ 16777216 +  1.2089258e+24 + infinit + 2.0589113e+14 ) -2 + 4.7683716e+14

= ( 2+ 16777216 + 2.0589113e+14 ) : ( 1+ 16777216 + infinit) -2 + 4.7683716e+14

= (2.0589115e+14 : infinit ) + 4.7683716e+14
= 0 + 4.7683716e+14= 4.7683716e+14 = 4.7683716 X 2.71828182846 + 14

= 26.9617778716

,,e" este o constanta care este egala cu 2.71828182846

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