Răspuns :
aceasta problema se rezolva cu segmente eu o sa pun ___
___
___+20
___+20+20
___+20+20+20
acolada 412
412-(20+20+20+20+20+20)=412-120=292
292:4=73
73+20+20=113
___
___+20
___+20+20
___+20+20+20
acolada 412
412-(20+20+20+20+20+20)=412-120=292
292:4=73
73+20+20=113
412-20-40-60=292
292:4=73 km ziua 1
73+20=93 ziua2
93+20 =113 ziua 3
113+20=133 ziua 4
292:4=73 km ziua 1
73+20=93 ziua2
93+20 =113 ziua 3
113+20=133 ziua 4