a) Aterasa= 40x20 x2 - 10x10 =1600-100=1500 m²
b) folie hidroizolanta= 1500×3 × 110%=4950 m²
c)
distanta cea mai mare AG
prelungim Ab si FG pana se intersecteaza in P
BP=20-10=10
AP=AB+BP=20+10=30
PF=40-10=30
PG=PF+FG=30+40=70
AG=√(30²+70²)=√(900+4900)=√5800≈≈76,15 <80 m
