Răspuns :
[tex]7+14+21+...+210= 7(1+2+3+....+30) \\\\\\ S= 7* \frac{\not 30*(1+30)}{\not 2} \\\\ S= 7*15*31 \\\\ \boxed{S=3255}[/tex]
Il dam pe 7 factor comun:
7 x( 1+2+3+....+30)
formula: [tex] \frac{n(n+1)}{2} [/tex]
n=30
7x[tex] \frac{30x(30+1)}{2} [/tex]= 7x[tex] \frac{30x31}{2} [/tex]= 7x 456=3255
Nu sunt sigura, dar cred ca asa se procedeaza! Sper sa fie bine!
7 x( 1+2+3+....+30)
formula: [tex] \frac{n(n+1)}{2} [/tex]
n=30
7x[tex] \frac{30x(30+1)}{2} [/tex]= 7x[tex] \frac{30x31}{2} [/tex]= 7x 456=3255
Nu sunt sigura, dar cred ca asa se procedeaza! Sper sa fie bine!