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Laurllaauurr
a fost răspuns

2(4x~2-6x+5)-3(2x~2-5x+4)-2(x~2-4x-2)

~2= la puterea a 2-a

Răspuns :

Miky93
[tex]2(4x^2-6x+5)-3(2x^2-5x+4)-2(x^2-4x-2)= \\\\= 8x^2-12x+10-6x^2+15x-12-2x^2+8x+4= \\\\ = 8x^2-8x^2-12x+23x+14-12= \\\\ = \boxed{11x+2} [/tex]

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