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Calculati dand factor comun: 
a) 5³⁰-5²⁹-5²⁸=
b) 2³²+2²⁹+2²⁸=
c) 9x2¹⁰⁰-2⁹⁹x5-3x2¹⁰¹=

Răspuns :

CarMina03
a) 5³⁰-5²⁹-5²⁸=5²⁸(5²-5-1)=5²⁸*19
b) 2³²+2²⁹+2²⁸=2²⁸(2⁴+2+1)=2²⁸*19
c) 9x2¹⁰⁰-2⁹⁹x5-3x2¹⁰¹=2⁹⁹(9*2-5-3*2²)=2⁹⁹(18-5-12)=2⁹⁹
MFM
5^28(5²-5-1)=5^28.(25-5-1)=19.5^28
b) 2^28(2^4+2+1)=19.2^28
2^99(18-5-12)=2^99
2^99 -2 la puterea 99

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