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calculati masa de benzen de puritate 75% necesara obtinerii a 67,5 kg clorobenzen, la un randament de 80%.

Răspuns :

n=mp/mt*100==>mt=mp*100/n=6750/80=84.375 kg C6H5-Cl

78kg....................112.5kg
C6H6 + Cl2 ---> C6H5-Cl + HCl
x=58.5kg.............84.375kg

puritatea=mpur/mimpur*100==>mimpur=mpur*100/puritate=58.5*100/75=78 Kg C6H6 impur

MC6H6=78kg/kmol
MC6H5-Cl=112.5kg/kmol

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