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Calculati:
a) 3x(x²-5x+1)-2x²(x+7)-3x+1=
b)xy(x+y-1)-3x²(y-x+1)+2x(x+y)=
c)x(x+1)-(x-2)(2x+1)+4x-9=

Răspuns :

Renatemambouko
a) 3x(x²-5x+1)-2x²(x+7)-3x+1=
= 3x³-15x²+3x-2x³-14x²-3x+1=
= x³-29x²+1

b)xy(x+y-1)-3x²(y-x+1)+2x(x+y)=
=x²y+xy²-xy-3x²y+3x³-3x²+2x²+2xy=
=xy²-2x²y+3x³-x²+xy

c)x(x+1)-(x-2)(2x+1)+4x-9=
=x²+x-2x²+4x-x+2+4x-9=
=-x²+8x-7

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