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a fost răspuns

Calculati media geometrica a numerelor reale:
a) √30-12√6-√4+2√3+3√5-2√6+5
b)2√8-√14+4√6-√22+4√10

Răspuns :

HyperCoder
[tex]a= \sqrt{30}-12 \sqrt{6}- \sqrt{4}+2 \sqrt{3}+3 \sqrt{5}-2 \sqrt{6} +5[/tex]
[tex]a= \sqrt{30}-12 \sqrt{6}+2 \sqrt{3}+3 \sqrt{5}-2 \sqrt{6} +3[/tex]
[tex]a= \sqrt{30}-14\sqrt{6}+2 \sqrt{3}+3 \sqrt{5} +3[/tex]

[tex]b=2\sqrt{8}- \sqrt{14}+4 \sqrt{6}- \sqrt{22} +4+ \sqrt{10}[/tex]
[tex]b=2*(2 \sqrt{2} )- \sqrt{14}+4 \sqrt{6}- \sqrt{22} +4+ \sqrt{10}[/tex]
[tex]b=4 \sqrt{2} - \sqrt{14}+4 \sqrt{6}- \sqrt{22} +4+ \sqrt{10} [/tex]

[tex]m_g= \sqrt{a*b} [/tex]
[tex]m_g= \sqrt{(\sqrt{30}-14\sqrt{6}+2 \sqrt{3}+3 \sqrt{5} +3)*(4 \sqrt{2} - \sqrt{14}+4 \sqrt{6}- \sqrt{22} +4+ \sqrt{10})}[/tex]
De aici cred ca te descurci ;)

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