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EXERCITIUL.3 uN BICICLIST A PARCURS UN DRUM IN TREI ZILE ASTFEL :IN PRIMA ZI 20%DIN DRUM,A DOUA ZI 25%din rest si a treia zi 9 km.aflati cat aparcurs biciclistul in prima zi.AJUTA-TI-MA VAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA ROOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGG FRUMOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS

Răspuns :

Renatemambouko
x=lungime drum
20%x=x/5=ziua 1
x-x/5=4x/5=rest
4x/5×25%=4x/5×1/4=x/5=ziua 2

x/5+x/5+9=x
x+x+45=5x
3x=45
x=15 km (lungime drum)

15×20%=3 km a parcurs in ziua 1

Alivas4
prima zi:20%
a doua zi: 1/4 din 80% 80:4=20%
a treia zi :100%-(20%+20%)=60%
daca 9 km=60% atunci 20% =(9x20):60=3km
in prima zi a parcurs 3 km

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