Răspuns :
x=5
y+z=14
a) x+2y+2z=
=5+2(y+z)=
=5+2*14=
=5+28=33
b) 5x+3y+3z=
=5*5+3(y+z)=
=25+3*14=
=25+42=67
y+z=14
a) x+2y+2z=
=5+2(y+z)=
=5+2*14=
=5+28=33
b) 5x+3y+3z=
=5*5+3(y+z)=
=25+3*14=
=25+42=67
x+y=56
y+z=88
x+z=80
a) x+2y+2z=x+2(y+z)= 5+2*14=5+28=33
b) 5x+3y+3z=5x+3(y+z)=5*5+3*14=25+42= 67
y+z=88
x+z=80
a) x+2y+2z=x+2(y+z)= 5+2*14=5+28=33
b) 5x+3y+3z=5x+3(y+z)=5*5+3*14=25+42= 67